Overlay Images List¶
Combines two images by layering the first (top port) image on top of the other (bottom port) image , with choice for combining operator. Images must have the same number of channels
Documentation¶
Algorithms¶
- additive
Adds the two images together where they overlap.
- use alpha channel:
Use last channel of source images as alpha channel
- alpha:
Alpha value used when no alpha channel is given
- divide
Divides bottom image by all other images, one at a time.
- use alpha channel:
Use last channel of source images as alpha channel
- alpha:
Alpha value used when no alpha channel is given
- layer
Layers on image on top of the other, alpha channel (if any) determines transparency. Otherwise alpha value below
- use alpha channel:
Use last channel of source images as alpha channel
- alpha:
Alpha value used when no alpha channel is given
- max
Takes the maximum value of the images.
- use alpha channel:
Use last channel of source images as alpha channel
- alpha:
Alpha value used when no alpha channel is given
- median
Takes the median value of the images.
- use alpha channel:
Use last channel of source images as alpha channel
- alpha:
Alpha value used when no alpha channel is given
- min
Takes the minimum value of the images.
- use alpha channel:
Use last channel of source images as alpha channel
- alpha:
Alpha value used when no alpha channel is given
- multiplicative
Multiplies images where they overlap.
- use alpha channel:
Use last channel of source images as alpha channel
- alpha:
Alpha value used when no alpha channel is given
- subtract
Subtracts top image from bottom.
- use alpha channel:
Use last channel of source images as alpha channel
- alpha:
Alpha value used when no alpha channel is given
Definition¶
Input ports¶
- images [image]
Input images
Output ports¶
- result image
result after filtering
Configuration¶
- Algorithm (algorithm)
(no description)
- alpha (alpha)
(no description)
- use alpha channel (use alpha channel)
(no description)
Implementation¶
- class node_layers.OverlayImagesList[source]